Answer:
1) v_i = 2.78 m/s
v_f = 16.67 m/s
t = 5 s
Acceleration = 2.78 m/s²
2) a = 1.5 m/s²
Step-by-step explanation:
1) The car was running at 10 km/hr.
In m/s this is 2.78 m/s
Thus;
Initial velocity; v_i = 2.78 m/s
It increased its speed to 60 km/hr in 5 seconds.
Thus, final velocity is 60 km/hr
Converting to m/s gives; 16.67 m/s
Final velocity; v_f = 16.67 m/s
Time to reach final velocity; t = 5 seconds
From Newton's first equation of motion, we can find the acceleration;
a = (v_f - v_i)/t
a = (16.67 - 2.78)/5
a = 2.78 m/s²
2) started from test, so initial velocity;
v_i = 0 m/s
Reached a speed of 9 m/s in 6 seconds.
Final velocity; v_f = 9 m/s
Time; t = 6 s
Acceleration is calculated as;
a = (v_f - v_i)/t
a = (9 - 0)/6
a = 1.5 m/s²
