Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
Answer:
V₂ = 2.0 Liters at STP conditions
Explanation:
Solving problem using the combined gas law
Given:
Case I Conditions Cast II Conditions
P₁ = 825mmHg P₂ = 760mm
V₁ = 2.30 Liters V₂ = ?
T₁ = 70°C + 273 = 343K T₂ = 0°C = 273K
Substitute into combined gas law assuming moles of gas remains constant; solve for unknown volume under case 2 conditions
P₁·V₁/n₁·T₁ = P₂·V₂/n₂T₂ => V₂ = P₁·V₁·T₂ / P₂·T₁ => note: in this solution, moles of gas remains constant as is disregarded in final calculation.
V₂ = (825mm)(2.3L)(273K) / (760mm)(343K) = 1.987 Liters (calculator answer) ≅ 1.9 Liters (2 sig figs based on given volume (V₁)
V₂ = 1.987 Liters ≅ 2.0 Liters (2 sig figs based on given volume (V₁)
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.