Answered

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how many grams are there in 1.77 x 10^22 atoms of beryllium

Sagot :

drpelezo

Answer:

0.265 grams Be (3 sig. figs. per coefficient of given 1.77 x 10²² atoms Be)

Explanation:

Calculation Sequence: #atoms => #moles by dividing by Avogadro's Number (6.02 x10²³) => #grams (multiply #moles by Be formula weight - 9.012g/mol

Given 1.77 x 10²² atoms Be = 1.77 x 10²² atoms Be x 1 mole Be/6.02 x 10²³ atoms Be/mole Be x 9.012 g Be/mole Be = 0.26497 (calculator answer)

= 0.265 grams Be (3 sig. figs. per coefficient of given 1.77 x 10²² atoms Be)

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