Answered

Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

A factory produces steel components for use by a number of different
companies. The density of the steel used by the factory is 8000 kg/mº,
A partoutor steel oube produced by the factory has a side length of 5 em,
5 cm
5 cm
5cm
Calculate the mass of one of these cubes. Write your answer in
kilograms

Sagot :

oladayoademosu

Answer:

1 kg

Explanation:

Since density ρ = m/v where m = mass of steel cube and v = volume of steel cube = L³ where L= side length of steel cube = 5 cm = 0.05 m

Now, m =  ρv =  ρL³

Since  ρ = 8000 kg/m³,

m = ρL³

= 8000 kg/m³ × (0.05 m)³

= 8000 kg/m³ × 0.000125 m³

= 1 kg

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.