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A factory produces steel components for use by a number of different
companies. The density of the steel used by the factory is 8000 kg/mº,
A partoutor steel oube produced by the factory has a side length of 5 em,
5 cm
5 cm
5cm
Calculate the mass of one of these cubes. Write your answer in
kilograms

Sagot :

oladayoademosu

Answer:

1 kg

Explanation:

Since density ρ = m/v where m = mass of steel cube and v = volume of steel cube = L³ where L= side length of steel cube = 5 cm = 0.05 m

Now, m =  ρv =  ρL³

Since  ρ = 8000 kg/m³,

m = ρL³

= 8000 kg/m³ × (0.05 m)³

= 8000 kg/m³ × 0.000125 m³

= 1 kg

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