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find the gradient of a line that is perpendicular to 8y+4x=5​

Sagot :

Answer:

gradient = 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope (gradient) and c the y- intercept )

Given

8y + 4x = 5 ( subtract 4x from both sides )

8y = - 4x + 5 ( divide the terms by 8 )

y = - [tex]\frac{1}{2}[/tex] x + [tex]\frac{5}{8}[/tex] ← in slope- intercept form

with gradient = - [tex]\frac{1}{2}[/tex]

Given a line with gradient m then the gradient of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-\frac{1}{2} }[/tex] = 2

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