corgiperson789
Answered

Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

helppppp meeeeee the sum of the squares of three consecutive integer numbers is 1454. Find the numbers. but i found 21 22 and 23. you need to find the other set plzzz​

Sagot :

maviadallepalle

Step-by-step explanation:

A=x

B=x+1

C=x+2

[tex] {x}^{2} + {(x + 1)}^{2} + {(x + 2)}^{2} = 1454 \\ {x}^{2} + {x}^{2} + 2x + 1 + {x}^{2} + 4x + 4 = 1454 \\ 3{x}^{2} + 6x + 5 - 1454 = 0 \\ 3 {x}^{2} + 6x - 1449 = 0 \\ {x}^{2} + 2x - 483 = 0 [/tex]

I'm sorry but I can't use the calculator, I hope this helps you anyway.

Answer:

The two sets would be 21,22,23 and -21, -22, and -23

Step-by-step explanation:

This is because a negative number squared would be positive.

So -21^2+-22^2+-23^2 would equal the same as 21^2+22^2+23^2 which would be 1454.

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.