swarayibrahimmaada
Answered

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X^2/3-5X^1/3+6=0
find x​

Sagot :

boffeemadrid

Answer:

[tex]x=27,8[/tex]

Explanation:

The equation is

[tex]x^{\dfrac{2}{3}}-5x^{\dfrac{1}{3}}+6=0[/tex]

Let,

[tex]x^{\dfrac{1}{3}}=y[/tex]

So,

[tex]y^2-5y+6=0\\\Rightarrow y=\dfrac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\times 1\times 6}}{2\times 1}\\\Rightarrow y=3,2[/tex]

[tex]x^{\dfrac{1}{3}}=y\\\Rightarrow y^3=x\\\Rightarrow x=3^3\\\Rightarrow x=27[/tex]

[tex]x=2^3\\\Rightarrow x=8[/tex]

Hence, [tex]x=27,8[/tex].

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