kerbalman0
Answered

Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

a piece of clay with mass m is traveling with an unknown velocity in the positive x-direction, when it collides and sticks to a block of mass 3m, moving with velocity v=-3m/s. after the collision, the block and clay are stuck together and traveling with a velocity of 1 m/s in the negative x-direction. what was the original velocity of the clay mass?

Sagot :

jcherry99

Answer:

13 m in the + x direction.

Explanation:

Givens

m1 = m

m2 = 3m

v1= ? = x

v2 = - 3 m/s

v3 = v4 = - 1 m/s

Equation

Let x be the speed of the lighter object before collision.

Momentum before collision = momentum after collision

Solution

mx   - 3m * 3m/s = (m1 + m2)*(-1)

m(x - 3*3m/s) = (m + 3m)(-1)

m(x - 9) = - 4m                                      Cancel the ms

x - 9 = 4                                                 Add 9 to both sides

x = 9 + 4

x = 13 m/s

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.