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Sagot :
Answer:
13 m in the + x direction.
Explanation:
Givens
m1 = m
m2 = 3m
v1= ? = x
v2 = - 3 m/s
v3 = v4 = - 1 m/s
Equation
Let x be the speed of the lighter object before collision.
Momentum before collision = momentum after collision
Solution
mx - 3m * 3m/s = (m1 + m2)*(-1)
m(x - 3*3m/s) = (m + 3m)(-1)
m(x - 9) = - 4m Cancel the ms
x - 9 = 4 Add 9 to both sides
x = 9 + 4
x = 13 m/s
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