kerbalman0
Answered

At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

a piece of clay with mass m is traveling with an unknown velocity in the positive x-direction, when it collides and sticks to a block of mass 3m, moving with velocity v=-3m/s. after the collision, the block and clay are stuck together and traveling with a velocity of 1 m/s in the negative x-direction. what was the original velocity of the clay mass?

Sagot :

boffeemadrid

Answer:

[tex]5\ \text{m/s}[/tex]

Explanation:

[tex]m_1[/tex] = Mass of clay = m

[tex]m_2[/tex] = Mass of block = 3m

[tex]u[/tex] = Velocity of clay

[tex]v[/tex] = Velocity of block = -3 m/s

[tex]v_c[/tex] = Velocity of combined mass = -1 m/s

As mometum in the system is conserved we get

[tex]m_1u+m_2v=(m_1+m_2)v_c\\\Rightarrow u=\dfrac{(m_1+m_2)v_c-m_2v}{m_1}\\\Rightarrow u=\dfrac{(m+3m)\times -1-3m\times -3}{m}\\\Rightarrow u=\dfrac{5m}{5}\\\Rightarrow u=5\ \text{m/s}[/tex]

The original velocity of the clay mass was [tex]5\ \text{m/s}[/tex].

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.