Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
9514 1404 393
Answer:
- P₂ and x are both supplementary to N₁
- Q₁
- R = 90° -x
- ΔSMP ≅ ΔSMR ∴ PS ≅ SR
Step-by-step explanation:
1. Angles P₂ and N₁ are opposite angles of inscribed quadrilateral PMNQ, so are supplementary. Angles N₁ and N₂ form a linear pair, so are supplementary. Angles supplementary to the same angle (N₁) are congruent, hence P₂ = x ≅ N₂
__
2. ΔPMQ is isosceles, so angle Q₁ is also congruent to x.
__
3. In ΔPMQ, the sum of angles is 180°, so ...
M₁ +2x = 180°
Dividing by 2 gives ...
M₁/2 +x = 90°
Angle M₁ subtends arc PQ of circle M. Angle R inscribed in circle M subtends the same arc, so ...
R = (M₁/2)
R = 90° -x
__
4. From the above, we know that angles N₂ and R are complementary (total 90°), so angle S₂ = 90°. Segment MS will only intersect chord PR at right angles at the midpoint of that chord.
Hence S is the midpoint of PR and PS = SR.
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.