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write the formula of the parabola that has x-intercepts (1.3,0) and (-1.3,0), and y-intercept (0,169)

Sagot :

kohai01

Answer:

y= 169 −  [tex]100^{2}[/tex]

Step-by-step explanation:

A parabola is a symmetrical plane curve that forms when a cone intersects with a plane parallel to its side.

Standard form of a quadratic function represent a parabola.

The equation of parabola is [tex]y=-x^{2} +1.69[/tex]

Parabola:

We have to find the formula for the parabola that has x- intercepts  [tex](1.3,0)[/tex] and [tex](-1.3,0)[/tex], and y- intercept [tex](0,1.69)[/tex]

So that, the intercept form of the quadratic equation is;

                    [tex]y=a(x-p)(x-q)[/tex]

where [tex](-1.3,0)=(p,0)[/tex]  and [tex](1.3,0)[/tex] is[tex](q,0)[/tex].

Since, with the vertex being at the y axis and the intercepts at the x axis means that the parabola opens down.

So that,

           [tex]1.69=a(0+1.3)(0-1.3)\\ \\1.69=-1.69 a\\ \\a=-1[/tex]

Substituting value of a in above equation.

           [tex]y=-1(x+1.3)(x-1.3)\\\\y=-1(x^{2}-1.69 )\\\\y=-x^{2} +1.69[/tex]

Hence, the equation of parabola is [tex]y=-x^{2} +1.69[/tex]

Learn more about the equation of parabola here:

https://brainly.com/question/4148030

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