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Evaluate the intensity of solar radiation for 6 September 2021 , given solar constant ( Isc ) = 1800 W / m2

Sagot :

Answer:

The answer is "[tex]1802.1978 \ \frac{w}{m^2}[/tex]"

Explanation:

The Solar radiation  reaches the earth surfaces is given by

[tex]I=Isc(1+0.033 \cos \frac{360.(n)}{365.25})[/tex]

where n is number of days in years

n for 6 September 2021:

[tex]\to n= 31+28+31+30+31+30+31+31+6\\\\\to n= 249[/tex]

[tex]\to I=Isc(1+0.033 \cos \frac{360 \alpha 249}{365.25})\\\\\to I=1800(1+0.033(+0.037))\\\\\to I =1800(1.001221)\\\\\to I=1802.1978 \ \frac{w}{m^2}[/tex]

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