The required sequence of ordered pairs is (6, 1), (8, 8), (12, 22), (20, 50). Option D is correct.
The first rule is to multiply by 2, then subtract 4 starting from 6. The second rule is to add 3, then multiply by 2 starting from 1. What are the first four ordered pairs using the two sequences to be determined?
What is arithmetic?
In mathematics, it deals with numbers of operations according to the statements.
Let the number be x for the first sequence and y for the second sequence.
The first rule is to multiply by 2, then subtract 4 starting from 6.
= 2x - 4
the sequence can be given as
6 is the first number
next number = 2(6) - 4
= 12-4
= 8
So the next term is 8. Similarly next 2 terms can be given as 12 and 20
Values of x = 6, 8, 12, 20
Now, the second rule is to add 3, then multiply by 2 starting from 1.
= (y + 3)2
First term = 1
Next term = (1 + 3)2
= 8
Similarly, the next two terms can be obtained.
y = 1, 8, 22, 50
Thus, the ordered pair can be formed as (6, 1), (8, 8), (12, 22), (20, 50).
Learn more about arithmetic here:
brainly.com/question/14753192
#SPJ2
