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Lindsey purchased a random sample of 25 tomatoes at the farmers market. The 95% confidence interval
for the mean weight of the tomatoes is 90.6 to 112.4 grams.
What is the Point Estimate?
What is the Margin of error?

Sagot :

Answer:

3 & 5

Step-by-step explanation:

The value of point estimate is 101.5 and value of margin of error is 10.9 gram if the Lindsey purchased a random sample of 25 tomatoes at the farmers market.

What is the margin of error(MOE)?

It is defined as an error that provides an estimate of the percentage of errors in real statistical data.

The formula for finding the MOE:

[tex]\rm MOE = Z\times \dfrac{s}{\sqrt{n}}[/tex]

Where   Z is the z-score at the confidence interval

            s is the standard deviation

            n is the number of samples.

Let's suppose m is a point estimate and ME is the margin of error.

The structure of the confidence interval is:

(m—ME, m + ME)

The given confidence interval is (90.6, 112.4)

Then, m—ME = 90.6 ..... (1)

m + ME = 112.4 ..... (2)

After solving equation (1) and (2) we get:

m = 101.5

ME = 10.9 grams

Thus, the value of point estimate is 101.5 and value of margin of error is 10.9 gram if the Lindsey purchased a random sample of 25 tomatoes at the farmers market.

Learn more about the Margin of error here:

brainly.com/question/13990500

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