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Sagot :

corm

Since this is a square, all of the sides are equal to each other.

That means we can take the two sides with an [tex]x[/tex] term in them (the bottom and the right ones) and set up an equation that has them equal to each other and then solve for [tex]x[/tex]:

[tex]3x = 5x - 4[/tex]

Let's move the terms with an [tex]x[/tex] to the left side of the equation:

[tex]3x - 5x = -4[/tex]

[tex]-2x = -4[/tex]

Now we can divide both sides by -2 to get [tex]x[/tex] by itself.

[tex]-2x = -4[/tex]

[tex]x = 2[/tex]

We can plug this into either of those sides to get the length of the sides of the square:

[tex]3x[/tex]

[tex]3(2)[/tex]

[tex]6[/tex]

Now that we know each side of the square is of length 6, we can take one of the remaining sides and set it equal to 6 and solve for [tex]y[/tex]:

[tex]5y + 1 = 6[/tex]

[tex]5y = 6 - 1[/tex]

[tex]5y = 5[/tex]

[tex]y = 1[/tex]

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