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URGENT PLEASE HELP The perimeter of AJKL is 106. Find the length of
midsegment ST.
J
5x +7
S
3x +3
4x-1
(not drawn to scale)
K
A
17
B
15
16
D
18

URGENT PLEASE HELP The Perimeter Of AJKL Is 106 Find The Length Of Midsegment ST J 5x 7 S 3x 3 4x1 Not Drawn To Scale K A 17 B 15 16 D 18 class=

Sagot :

mlarsen5000

Answer:

16

Step-by-step explanation:

3x+3+3x+3+5x+7+4x-1+4x-1=106

19x+11=106

19x=95

x=5

JL=5(5)+7=32

ST=1/2 of JL = 1/2 of 32 = 16

The length of midsegment ST will be 6. The perimeter of the triangle is given.

What is perimeter?

It's the sum of length of the sides used to make the given figure.

The perimeter of AJKL is 106;

⇒KS+SJ+JL+LT+TK=106

⇒3x+3+3x+3+5x+7+4x-1+4x-1=106

⇒19x+11=106

⇒19x=95

⇒x=5

The side JL is obtained by,x=5

JL=5x+7

JL=5×(5)+7

JL=32

The side ST is obtained

ST=(1/2)×JL

ST= 1/2 of 32

ST = 16

Hence, the length of midsegment ST will be 16.

Learn more about perimeter refer:

https://brainly.com/question/10466285

#SPJ2

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