Answered

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That minimum coefficient of static friction between the tyres and the road that will allow the car that will round safely.

Sagot :

Answer:

The answer is "[tex]0.13562748[/tex]"

Explanation:

Please find the complete question in the attached file.

Using formula:

[tex]\bold{U_s=\frac{v^2}{rg}}[/tex]

Given:

[tex]r=1.60 \times 10^2 \ m\\\\g=9.8\\\\v= 52.5\ \frac{km}{hr}= 14.583\ \frac{m}{s}[/tex]

put the value into the above-given formula:

[tex]U_s= \frac{14.583^2}{160 \times 9.8}[/tex]

    [tex]= \frac{212.663889}{1568}\\\\=0.13562748[/tex]

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