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A fair coin is tossed 6 times. What is the probability of getting H,H,T,T,H,T in that order?

Sagot :

jcherry99

Answer:

Step-by-step explanation:

The total number of ways a fair coin can land is 2^6 which is 64 times

The probability of any one of the 6 is 1/64 = 0.015625

The explanation is that there are two ways a coin can land. And each way is independent of the way it landed before. If you consistently get any other answer, then the coin is not a fair one.

  • Heads or tails   2
  • Heads or tails 2
  • Heads or tails 2
  • Heads or tails   2
  • Heads or tails 2
  • Heads or tails 2

The result is 2 * 2 * 2 * 2 * 2 *2 = 64

altavistard

Answer:

1/64

Step-by-step explanation:

The probability of getting an H is 1/2, the same of getting a T.

The tosses are all independent.  That is, P(H) = P(T) = 1/2, and one toss does not affect the next one in any way.

The desired probability is (1/2)^6 = 1/64.  The exponent 6 is used because 6 tosses occur.

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