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please explain in detail how you solved.​

Please Explain In Detail How You Solved class=

Sagot :

Step-by-step explanation:

Since this is a right triangle and we are given an angle measure that measure 45, the other angle measure also measure 45.

So this means we are dealing with a 45-45-90 triangle.

A 45-45-90 triangle legs are equal to each other and the hypotenuse measures sqr root of 2 times more than the legs.

The hypotenuse measure 2 times sqr root of 14 so divide by sqr root of 2 to find x and y.

[tex] \frac{2 \sqrt{14} }{1} \times \frac{1}{ \sqrt{2 } } = \frac{ \sqrt{56} }{ \sqrt{2} } = \sqrt{28} = 2 \sqrt{7} [/tex]

Since x and y are equal, they both measure

[tex]2 \sqrt{7} [/tex]