Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

1. A sample of helium gas in a balloon is compressed from 4.0L to 2.5L at a constant temperature. If the pressure
of the gas in the 4.0L volume is 210 kPa, what will be the pressure at 2.5L?

Sagot :

serranomarites31

Answer:

A sample of helium gas in a balloon is compressed from 4.0 L to 2.5 L at a constant temperature. If the pressure of the gas in the 4.0-L volume is 210 kPa, what will the pressure be at 2.5 L? P2 = 340 kPa (336 rounded to 2 s.f.)

Explanation:

sana makatulong

samueladesida43

The new pressure of the gas whose volume is changed from 4.0L to 2.5L is 336kPa.

BOYLE'S LAW:

  • The new pressure of a gas with a change in volume can be calculated by using Boyle's law equation as follows:

P1V1 = P2V2

Where;

  1. P1 = initial pressure (kPa)
  2. P2 = final pressure (kPa)
  3. V1 = initial volume (L)
  4. V2 = final volume (L)

  • According to this question, a sample of helium gas in a balloon is compressed from 4.0L to 2.5L at a constant temperature. The new pressure can be calculated as follows:

  • 210 × 4 = P2 × 2.5

  • 840 = 2.5P2

  • P2 = 840 ÷ 2.5

  • P2 = 336kPa.

  • Therefore, the new pressure of the gas whose volume is changed from 4.0L to 2.5L is 336kPa.

Learn more at: https://brainly.com/question/1437490?referrer=searchResults

We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.