Answered

At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

1. A sample of helium gas in a balloon is compressed from 4.0L to 2.5L at a constant temperature. If the pressure
of the gas in the 4.0L volume is 210 kPa, what will be the pressure at 2.5L?

Sagot :

serranomarites31

Answer:

A sample of helium gas in a balloon is compressed from 4.0 L to 2.5 L at a constant temperature. If the pressure of the gas in the 4.0-L volume is 210 kPa, what will the pressure be at 2.5 L? P2 = 340 kPa (336 rounded to 2 s.f.)

Explanation:

sana makatulong

samueladesida43

The new pressure of the gas whose volume is changed from 4.0L to 2.5L is 336kPa.

BOYLE'S LAW:

  • The new pressure of a gas with a change in volume can be calculated by using Boyle's law equation as follows:

P1V1 = P2V2

Where;

  1. P1 = initial pressure (kPa)
  2. P2 = final pressure (kPa)
  3. V1 = initial volume (L)
  4. V2 = final volume (L)

  • According to this question, a sample of helium gas in a balloon is compressed from 4.0L to 2.5L at a constant temperature. The new pressure can be calculated as follows:

  • 210 × 4 = P2 × 2.5

  • 840 = 2.5P2

  • P2 = 840 ÷ 2.5

  • P2 = 336kPa.

  • Therefore, the new pressure of the gas whose volume is changed from 4.0L to 2.5L is 336kPa.

Learn more at: https://brainly.com/question/1437490?referrer=searchResults

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.