Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
Answer:
[tex][H^+]=1.12x10^{-6}M[/tex]
[tex]pOH=8.05\\\\pH=5.95[/tex]
Explanation:
Hello there!
In this case, since the question is incomplete, but given the concentration of the hydroxide ions in the solution you are given, it is possible for us to calculate pH, pOH and [H+] as signals of acidity or basicity for the analyzed solution:
[tex]pOH=-log([OH^-])=-log(8.9x10^{-9})=8.05\\\\pH=14-pOH=14-8.05=5.95[/tex]
Next, once the pH is calculated, we can do the same for the concentration of hydrogen ions in the solution:
[tex][H^+]=10^{-pH}=10^{-5.95}=1.12x10^{-6}M[/tex]
Best regards!
We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.