Answered

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Mrs. Anderson has a bag of marbles. The first bag
contains 6 red marbles, 5 blue marbles, and 4 green
marbles. Mrs. Anderson will select 1 marble at random.
What is the probability that Mrs. Anderson will NOT
select a blue marble?

A. 1/3 B. 1/2 C. 1/10 D. 2/3

Sagot :

MrRoyal

Answer:

[tex]P(Not\ Blue) = \frac{2}{3}[/tex]

Step-by-step explanation:

Given

[tex]Red = 6[/tex]

[tex]Blue =5[/tex]

[tex]Green = 4[/tex]

Required

The probability of not selecting blue.

This means that any of the other colors is selected.

So, we have:

[tex]P(Not\ Blue) = P(Red) + P(Green)[/tex]

[tex]P(Not\ Blue) = \frac{Red}{Total} + \frac{Green}{Total}[/tex]

[tex]P(Not\ Blue) = \frac{6}{15} + \frac{4}{15}[/tex]

Take LCM

[tex]P(Not\ Blue) = \frac{6+4}{15}[/tex]

[tex]P(Not\ Blue) = \frac{10}{15}[/tex]

Divide by 5/5

[tex]P(Not\ Blue) = \frac{2}{3}[/tex]

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