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Sagot :
Answer:
9 mol H₂O
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
Chemistry
Atomic Structure
- Reading a Periodic Table
- Moles
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Stoichiometry
- Using Dimensional Analysis
- Analyzing reactions RxN
Explanation:
Step 1: Define
[RxN - Balanced] 6H₂ + O₂ → 3H₂O
[Given] 18 mol H₂
[Solve] mol H₂O
Step 2: Identify Conversions
[RxN] 6 mol H₂ → 3 mol H₂O
Step 3: Stoich
- [DA] Set up conversion: [tex]\displaystyle 18 \ mol \ H_2(\frac{3 \ mol \ H_2O}{6 \ mol \ H_2})[/tex]
- [DA] Simplify: [tex]\displaystyle 18 \ mol \ H_2(\frac{1 \ mol \ H_2O}{2 \ mol \ H_2})[/tex]
- [DA] Divide [Cancel out units]: [tex]\displaystyle 9 \ mol \ H_2O[/tex]
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