Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

If I start with.30 moles of AgNO3 and.35 moles of Li, what is my limiting reactant?

Sagot :

Answer:

AgNO₃ will be the limiting reagent.

Explanation:

The balanced reaction is:

AgNO₃ + Li → LiNO₃ + Ag

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate:

  • AgNO₃: 1 mole
  • Li: 1 mole
  • LiNO₃: 1 mole
  • Ag: 1 mole

To determine the limiting reagent, you can use a simple rule of three as follows: if by stoichiometry [tex]moles of AgNO_{3} =\frac{0.35 moles of Li*1 mole of AgNO_{3}}{1 mole of Li}[/tex]AgNO₃, how much moles of AgNO₃ will be needed if 0.35 moles of Li react?

moles of AgNO₃= 0.35

But 0.35 moles of AgNO₃ are not available, 0.30 moles are available. Since you have less moles than you need to react with 0.35 moles of Li, AgNO₃ will be the limiting reagent.