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Sagot :
Answer:
2.01 ; 1.918
Explanation:
Given the data:
X : ____ 0 __ 1 ___ 2 ___ 3 ____ 4 ____ 5
P(x) : 0.09 _ 0.32 _0.27_0.17___0.11 __ 0.04
The mean, E(x) :
Σ(X * p(x))
= (0*0.09)+(1*0.32)+(2*0.27)+(3*0.17)+(4*0.11)+(5*0.04) = 2.01
Standard deviation = sqrt(variance)
Variance = Var(x)
Var(X) = Σx²*p(x) - E(x)
Σ[(0^2 * 0.09) + (1^2 * 0.32) + (2^2 * 0.27) + (3^2 * 0.17) + (4^2 * 0.11) + (5^2 * 0.04)] - 2.01
= 5.69 - 2.01
= 3.68
SD(x) =sqrt(3.68)
SD(x) = 1.918
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