braaha
Answered

Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Experience the convenience of getting accurate answers to your questions from a dedicated community of professionals. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

An elevator accelerates from rest to a velocity of 12.0 m/sec as it rises 28.0 meters.  What was its’ acceleration, and for what time did it travel while it was accelerating?​

Sagot :

michaelodeniyi53

Answer:

given that

V = 12.0 m/s

U = 0 m/s

s = 28 m

Explanation:

using the equation of motion

V^2 = U^2 + 2as

12^2 = 0 + 2(28)a

144 = 56a

a = 5.5 m/s^2

v = u +at

12 = 0 + 5.5t

12 = 5.5t

t = 2.2s

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.