At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
Answer:
x₁ = 3.481 m
Explanation:
In this exercise the acceleration of the dog and the sled are given, for which we can use the kinematic relations.
Let's start by fixing a reference system located on the sled and suppose that it moves to the right, the sled acceleration a₁ = 0.2 m / s, the dog is on the other side of the rope, so if the acceleration is a₂ = -0.5 m / s2, the negative sign indicates that it is moving to the left.
The initial position of the sled is x₁₀ = 0 and the initial position of the dog is x₂₀ = 12.2 m, let's write the expressions for the position
x₁ = x₁₀ + v₁₀ t + ½ a₁ t²
x₂ = x₂₀ + v₂₀ t + ½ a₂ t²
in this case the two bodies start from rest so their initial velocities are zero
we substitute the values
x₁ = 0 + 0 + ½ (0.2) t²
x₂ = 12.2 + 0 + ½ (-0.5) t²
at the point where the two meet, the position is the same
x₁ = x₂
½ 0.2 t² = 12.2 - ½ 0.5 t²
(0.1 + 0.25) t² = 12.2
t = [tex]\sqrt{ \frac{12.2}{0.35} }[/tex]
t = 5.9 s
we look for the position of the sled (subscript 1)
x₁ = ½ 0.2 5.9²
x₁ = 3.481 m
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.
