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The 2nd term of an exponential sequence is 9 while the 4th term is 81.find the common ratio,the first term and the sum of the first five terms of the sequence

Sagot :

michals7241

Answer:

second term: 9

4th term:81

[tex](3rd \: term)^{2} = 9 \times 81[/tex]

=729

[tex] \sqrt{729} = 27[/tex]

3rd term=27

[tex] {9}^{2} = a1x27 \\ 81 = 27a1[/tex]

a1=3 the first term

[tex]81 = 3 \times {q}^{3} [/tex]

[tex] {q}^{3} = 27[/tex]

q=3

[tex]s = 3x \frac{1 - {3}^{5} }{1 - 3} = 364.5[/tex]

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