Answered

Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

The 2nd term of an exponential sequence is 9 while the 4th term is 81.find the common ratio,the first term and the sum of the first five terms of the sequence

Sagot :

michals7241

Answer:

second term: 9

4th term:81

[tex](3rd \: term)^{2} = 9 \times 81[/tex]

=729

[tex] \sqrt{729} = 27[/tex]

3rd term=27

[tex] {9}^{2} = a1x27 \\ 81 = 27a1[/tex]

a1=3 the first term

[tex]81 = 3 \times {q}^{3} [/tex]

[tex] {q}^{3} = 27[/tex]

q=3

[tex]s = 3x \frac{1 - {3}^{5} }{1 - 3} = 364.5[/tex]

Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.