zubariaali8
Answered

At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

a tennis ball is thrown straight up at a speed of 40m/s and caught at the same level. calculate rhe maximum height reached by the ball​

Sagot :

king3600

Answer:

81.6 m

Explanation:

Answer: 81.6 m.

The time it takes gravity to slow 40 m/s to zero when it teaches maximum height is

-v(initial) / -g = t

-40 m/s / -9.8 m/s^2 = 4.08 s

The height reached is the average velocity times this time 4.08 s, with v(avg) = [v(initial) + v(final)] / 2 with v(final) = 0. v(avg) = v(initial) / 2 = 40 m/s / 2 = 20 m/s.

So the distance d of maximum height is

d = v(avg)•t

d = 20 m/s • 4.08 s = 81.6 m.

Answer:

80m

Explanation:

time taken for stone to reach max-height is t=final velocity - intial velocity / acceleration due to gravity

t=v-u/g

where:

v=0 , u=40m/s ,g=-10m/so

: t=0-40/-10

t=4secs

: max-height reach=ut + 0.5gt²

=(40)(4)+(0.5)(-10)(4)I

=160-5(16)

=160-80

=80m

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.