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Sagot :
Step-by-step explanation:
Given
[tex]5y - 4 = 126(corresponding \: angles) \\ 5y = 126 + 4 \\ 5y = 130 \\ y = 130 \div 5 \\ = 26[/tex]
Also given
[tex]126 + (6z + 6) = 180(angles \: on \: a \: straight \: line) \\ 132 + 6z = 180 \\ 6z = 18 0 - 132 \\ 6z = 48 \\ z = 48 \div 6 \\ = 8[/tex]
Lastly,
[tex]x = 180 - 126 \\ = 54(angles \: on \: the \: same \: straight \: line \: and \: corresponding \: angles)[/tex]
Answer:
x = 126
y = 26
z = 8
Step-by-step explanation:
6z + 6 + 126 = 180
6z + 132 = 180
6z = 180 - 132
6z = 48
z = 8
6z + 6 + 5y - 4 = 180
6(8) + 6 + 5y - 4 = 180
48 + 2 + 5y = 180
50 + 5y = 180
5y = 180 - 50
5y = 130
y = 26
x = 126 (Because of alternate exterior angles thm)
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