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In circle A as shown below, segment DC is tangent to circle A at D.
Also, DC = 4 and BC = 2.

Find the length of the radius of circle A.
3
5
6
12.



In Circle A As Shown Below Segment DC Is Tangent To Circle A At D Also DC 4 And BC 2 Find The Length Of The Radius Of Circle A 3 5 6 12 class=

Sagot :

Answer:

AB = 3

Step-by-step explanation:

AB = AD

AB² + 4² = (AB + 2)²

AB² + 16 = AB² + 4AB + 4

combine like terms:

4AB = 12

AB = 3

Answer:

3 units

Step-by-step explanation:

Let the radius be x

Therefore, using pythagoras Theorem,

[tex] {4 {}^{2} + {x}^{2} } = (x + 2) {}^{2} \\ 16 + x {}^{2} = {x}^{2} + 4x + 4 \\ 4x + 4 = 16 \\ 4x = 12 \\ x = 3[/tex]