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Factor the following quadratic expression n^2+ 4n-12

Sagot :

Answer:

(n + 6)(n - 2)

Step-by-step explanation:

Given

n² + 4n - 12

Consider the factors of the constant term (- 12) which sum to give the coefficient of the n- term (+ 4)

The factors are + 6 and - 2 , since

6 × - 2 = - 12 and 6 - 2 = + 4

Then

n² + 4n - 12 = (n + 6)(n - 2) ← in factored form