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ex² - 7x² - 10x+16=0​

Sagot :

Answer:

x is approximately equal to 1.09 and -3.43.

Step-by-step explanation:

I'm going to assume here that the "e" in question is the constant e ≈ 2.71828

In that case let's solve it by completing the square.

ex² - 7x² - 10x + 16 = 0

(e - 7)x² - 10x + 16 = 0

At this point, for simplicity, I'm going to refer to e - 7 as c, given that it's a constant number (roughly -4.28173).  So we'll rewrite that as:

cx² - 10x + 16 = 0

cx² - 10x = -16

c²x² - 10cx = -16c

c²x² - 10cx + 25 = -16c + 25

(cx - 5)² = 25 - 16c

cx - 5 = ± √(25 - 16c)

cx = 5 ± √(25 - 16c)

x = (5 ± √(25 - 16c)) / c

Now we can plug the value of "c" back in and solve for x:

x = (5 ± √(25 - 16(e - 7))) / (e - 7)

x ≈ (5 ± √(25 + 16 × 4.28173)) / -4.28173

x ≈ (5 ± √93.50768) / -4.28173

x ≈ (5 ± 9.67) / -4.28173

x ≈ 14.67 / -4.28 ≈ -3.43

x ≈ -4.67 / -4.28  ≈ 1.09

So x is approximately equal to 1.09 and -3.43.