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Sagot :

Answer: 824.6 g of NaCl are produced from 500.0 g of chlorine.

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]  [tex]\text{Moles of} Cl_2=\frac{500.00g}{71g/mol}=7.04moles[/tex]

[tex]2Na+Cl_2\rightarrow 2NaCl[/tex]  

According to stoichiometry :

1 mole of [tex]Cl_2[/tex] produce = 2 moles of [tex]NaCl[/tex]

Thus 7.04 moles of [tex]Cl_2[/tex] will produce=[tex]\frac{2}{1}\times 7.04=14.08moles[/tex]  of [tex]NaCl[/tex]

Mass of [tex]NaCl=moles\times {\text {Molar mass}}=14.08moles\times 58.5g/mol=824.26g[/tex]

Thus 824.6 g of NaCl are produced from 500.0 g of chlorine.

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