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Sagot :
Answer:
[HI] = 0.0255M
[H₂] = 0.00466M
[I₂] = 0.00257M
Explanation:
Para la reacción:
H₂(g) + I₂(g) ⇄ 2HI(g)
La constante de equilibrio, K, se define como:
54.3 = [HI]² / [H₂] [I₂]
Donde cada concentración [] será la concentración en equilibrio para cada especie
Para saber la dirección del equilibrio definiremos Q como:
Q = [HI]² / [H₂] [I₂]
Donde las concentraciones [] serán las concentraciones actuales de cada gas
Reemplazando:
Q = [0.0224M]² / [0.00623M] [0.00414M]
Q = 19.5
Como Q<K, la reacción se desplazará hacia la derecha produciendo más [HI]. Así, las concentraciones en equilibrio serán:
[HI] = 0.0224M +2X
[H₂] = 0.00623M - X
[I₂] = 0.00414 - X
54.3 = [0.0224M +2X]² / [0.00623M - X] [0.00414M - X]
54.3 = 0.00050176 + 0.0896 X + 4 X² / 0.0000257922 - 0.01037 X + X²
0.00140052 - 0.563091 X + 54.3 X² = 0.00050176 + 0.0896 X + 4 X²
0.00089876 - 0.652691 X + 50.3 X² = 0
Resolviendo la ecuación cuadrática:
X = 0.001566M → Solución verdadera
X = 0.01141M → Falsa solución. Produciría concentraciones negativas
Reemplazando:
[HI] = 0.0224M +2*0.001566M
[H₂] = 0.00623M - 0.001566M
[I₂] = 0.00414 - 0.001566M
[HI] = 0.0255M
[H₂] = 0.00466M
[I₂] = 0.00257M
Siendo estas últimas, las concentraciones de las especies luego de alcanzar el equilibrio.
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