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Find the value of x in the picture below. (round to nearest tenth if needed) THANK YOU FOR HELPING ME:)

Find The Value Of X In The Picture Below Round To Nearest Tenth If Needed THANK YOU FOR HELPING ME class=

Sagot :

Answer:

x ≈ 9.6

Step-by-step explanation:

Using Pythagoras' identity in the right triangle, that is

x² + 14² = 17²

x² + 196 = 289 ( subtract 196 from both sides )

x² = 93 ( take the square root of both sides )

x = [tex]\sqrt{93}[/tex] ≈ 9.6 (to the nearest tenth )

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