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The length of a rectangle is 3ft less than double the width, and the area of the rectangle is 14ft^2 find the dimensions of rectangle.

Sagot :

Answer: [tex]4\times 3.5\ ft^2[/tex]

Step-by-step explanation:

Given

area of the rectangle is [tex]A=14\ ft^2[/tex]

Suppose width is given by w

So, length is [tex]l=2w-3[/tex]

The area of a rectangle is [tex]A=l\times w[/tex]

putting values

[tex]\Rightarrow A=(2w-3)w\\\Rightarrow 14=2w^2-3w\\\Rightarrow 2w^2-3w-14=0\\\Rightarrow 2w^2-7w+4w-14=0\\\Rightarrow w(2w-7)+2(2w-7)=0\\\Rightarrow (2w-7)(w+2)=0\\\\\Rightarrow w=\dfrac{7}{2}\ ft[/tex]

length is [tex]l=4\ ft[/tex]

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