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the blood speed in a normal segment of a horizontal artery is 0.15 m/s. An abnormal segment of the artery is narrowed by an arteriosclerotic plaque down to one fifth its normal cross sectional area. What is the difference in blood preassures between the normal and constricted segments of the artery. The density of the blood is 1060

Sagot :

batolisis

Answer:

286.2  pa

Explanation:

Blood speed in a normal segment of a horizontal artery ( v2 ) = 0.15 m/s

Density of blood = 1060 kg/m^3

Normal sectional area = A2

constricted sectional area ( A1 )= 1/5 A2

Determine the difference in blood pressures between the normal and constricted segments

we will apply Equation of continuity     Av = constant

Δ p = 12 PV^2

     = 12 * 1060 * ( 0.15 )^2

     = 12720 * 0.0225  =  286.2  pa

attached below is a detailed solution of the Given problem

View image batolisis
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