Answered

Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

The left end of a spring is attached to a wall. When Bob pulls on the right end with a 200 N force, he stretches the spring by 20 cm. The same spring is then used for a tug-of-war between Bob and Carlos. Each pulls on his end of the spring with a 200 N force. How far does the spring stretch

Sagot :

oladayoademosu

Answer:

40 cm

Explanation:

Since Bob pulls with a force of F = 200 N when the spring is attached to the wall and it extends a length x = 20 cm, from Hooke's law,

F = kx where k = spring constant

So, k = F/x = 200 N/20 cm = 10 N/cm

Now, sine both Bob and Carlos pull with a force of F = 200 N in opposite directions, the spring stretches about its center and has an extension, x' in each direction.

So, from F = kx

x = F/k = 200 N/10 N/cm = 20 cm

So, the spring stretches 20 cm in both directions.

So, the total extension is thus x' + x' = 2x' = 2(20 cm) = 40 cm

The spring will stretch 40 cm.When a force is act om the spring the spring will stretch or compress depeds on the application of force.

What is hooke's law?

Hooke's law states that the force used to extend the spring is directly equal to the amount of stretch.

The force needed to extend the spring is proportional to its displacement. It is stated as

F=Kx

The given data in the problem is;

F is the force of pull to bob=  200 N

x is the length of extension= 20 cm.

F' is the force act on the another end=  200 N

According to Hooke's law,

[tex]\rm F = Kx \\\\ \rm K= \frac{F}{x} \\\\ \rm K= \frac{200}{20} \\\\ \rm K=10 \ N/cm[/tex]

The extension due to another end force is found by;

[tex]\rm x' = \frac{F}{K} \\\\ \rm x' = \frac{200}{10} \\\\ \rm x' = 20[/tex]

The total extension of the spring will be;

[tex]\rm x_t = x+x' \\\\ \rm x_t = 2(20) \\\\ \rm x_t =40\ cm[/tex]

Hence the spring will stretch 40 cm.

To learn more about the hooke's law refer to the link;

https://brainly.com/question/13348278

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.