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Sagot :
Answer:
b. No
Step-by-step explanation:
Binomial approximation to the normal:
Binomial distribution has n trials, with p probability.
If
[tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], it can be approximated to the normal distribution.
Assume the probability that a given student will not pass their college placement exam is 98%.
This means that [tex]p = 0.98[/tex]
134 students:
This means that [tex]n = 134[/tex]
Necessary conditions:
[tex]np = 134*0.98 = 131.32 \geq 10[/tex]
[tex]n(1-p) = 134*0.02 = 2.68 < 10[/tex]
Since the necessary condition n(1-p) < 10 is not satisfied, the answer is No, given by option b.
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