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A man's speed is 50 m/s and his mass is 120 kg. What is his kinetic energy just before running back up? |
kg*m/s


Sagot :

Answer:

150,000 Joules

Explanation:

KE= 1/2 *mv^2

1/2 * 120 *50^2

60*2500

150,000 Joules

Hope this helps :)