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Sagot :
Answer:
25% of the progeny is expected to be dihybrid, BbFf, expressing Black and short fur
Explanation:
Available data:
- the allele for black fur (B) is dominant over the allele for brown fur (b)
- the allele for short fur (F) is dominant over the allele for long fur (f)
- Cross: BbFf x bbff
Parentals) BbFf x bbff
Phenotypes) Black/Short Brown/Long
Gametes) BF, Bf, bF, bf bf, bf, bf, bf
Punnett square) BF Bf bF bf
bf BbFf Bbff bbFf bbff
bf BbFf Bbff bbFf bbff
bf BbFf Bbff bbFf bbff
bf BbFf Bbff bbFf bbff
F1) 4/16 = 1/4 = 25% of the progeny is expected to be dihybrid, BbFf, expressing Black and short fur
4/16 = 1/4 = 25% of the progeny is expected to be bbFf, expressing Brown and short fur
4/16 = 1/4 = 25% of the progeny is expected to be Bbff, expressing Black and long fur
4/16 = 1/4 = 25% of the progeny is expected to be bbff, expressing Brown and Long fur
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