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Sagot :
Answer:
A)P(ACC has a team in the championship game) = 0.5
B)P(SEC has a team in the championship game) = 0.4
C)P(both ACC & SEC having teams in the championship games) = 0.05
D)P(ACC or SEC) = 0.85
E)P(not ACC or SEC) = 0.15
Step-by-step explanation:
A) We are told that in the last 20 years, ACC has had a team in the championship game for 10 times.
Thus;
P(ACC has a team in the championship game) = 10/20 = 0.5
B) SEC has a team in the championship game 8 times in the last 20 years;
Thus;
P(SEC has a team in the championship game) = 8/20 = 0.4
C) since both ACC and SEC have had teams in the championship game for the past 20 years, then;
P(both ACC & SEC having teams in the championship games) = 1/20 = 0.05
D) Addition rule of probability is that;
P(A or B) = P(A) + P(B) - P(A & B)
Applying it to this question, we have;
P(ACC or SEC) = P(ACC) + P(SEC) - P(ACC & SEC)
Plugging in the relevant values, we have;
P(ACC or SEC) = 0.5 + 0.4 - 0.05
P(ACC or SEC) = 0.85
E) from complement rule, we can find the probability that the championship game will not a have team from one of these two conferences.
Thus;
P(ACC not SEC) = 1 - P(ACC or SEC)
P(ACC not SEC) = 1 - 0.85
P(ACC not SEC) = 0.15
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