At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

How do I solve for the missing side lengths. My sender has to be as a radical in simplest form.

How Do I Solve For The Missing Side Lengths My Sender Has To Be As A Radical In Simplest Form class=

Sagot :

Answer: 6√6

Step-by-step explanation: When an angle is 45 degrees in a triangle it is actually half a square (I know right!!!), so, therefore, the other side length will also be 6, and then using the Pythagorean theorem we get the hypotenuse to be 6√2. Now, when an angle is 60 degrees in a triangle it is actually half an equilateral triangle (I know right!!!), so, therefore, the other side length will be double the length, 12√2, and using the Pythagorean theorem we get the side length x to be 6√6! Hope this helps!

We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.