Answered

Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

Pioneer company has given an aptitude test to 71 potential job applicants. The test score had an average of 81 and a standard deviation of 8. Aptitude tests are known to follow a t-distribution. Pioneer rejects the bottom 5% of the applicants right away. The top 5% are hired immediately at managerial positions.
A. What is the degrees of freedom for this distribution?
B. What is the t-score for someone who has scored 93?
C. What is the cutoff score for those who'll be hired as managers?
D. What will be the cutoff score fro those who'll get rejected right away?
E. If we want to define the middle of the class (80%) to be average, what will be the lower cut-off scores?
F. If we want to define the middle of the class (80%) to be average, what will be the upper cut-off scores?

Sagot :

Answer:

Follows are the solution to the given points:

Step-by-step explanation:

In point A:

[tex]\to df = n - 1 = 71-1= 70[/tex]

In point B:

[tex]\to t = \frac{(x -X)}{s} = \frac{(93-81)}{8} = \frac{12}{8}= 1.5[/tex]

In point C:

For df = 70, the top 5% critical t score

tcrit = 1.666914479

Thus,

[tex]\to 1.666914479 = \frac{(x - 81)}{8}\\\\\to 1.666914479 \times 8 = (x - 81)\\\\\to 13.335315832 = (x - 81)\\\\\to 13.335315832 +81 =x \\\\\to x= 94.335315832[/tex]

In point D:

For df = 70, the top 5% critical t score

tcrit = -1.666914479

[tex]\to -1.666914479 = \frac{(x - 81)}{8}\\\\\to -1.666914479 \times 8= (x - 81)\\\\\to -13.335315832= (x - 81)\\\\\to -13.335315832+81 = x \\\\\to x = 67.664684168\\\\[/tex]

In point E:

The lower cutoff is 0.10 in the center, which would be around 80 %. The critical point therefore is

tcrit = -1.293762898

[tex]\to -1.293762898 = \frac{(x-81)}{8}\\\\\to -1.293762898 \times 8= (x-81) \\\\\to -1.293762898 \times 8= (x-81) \\\\\to -10.350103184=x-81\\\\\to -10.350103184+81=x\\\\\to x=70.649896816[/tex]

In point F:

The lower cutoff is 0.90 in the center, which would be around 80 %. The critical point therefore is

tcrit = 1.293762898

[tex]\to 1.293762898 = \frac{(x-81)}{8}\\\\\to 1.293762898 \times 8= x-81\\\\\to 10.350103184 =x-81\\\\\to 10.350103184 +81=x\\\\\to x = 91.350103184\\[/tex]

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.