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Sagot :
Answer:
A) The parameter of interest is the average filling weight of all cereal packages. ;
Point estimate = 1.22
Margin of Error = 0.0196
Confidence interval = (1.2004, 1.2396)
C) No, since the confidence interval contains the target filling weight of 1.20.
Step-by-step explanation:
A) The parameter of interest is the average filling weight of all cereal packages.
The point estimate = sample mean = 1.22
The margin of error with 95% confidence :
Zcritical * σ/sqrt(n)
Zcritical at 95% confidence = 1.96
Margin of Error = 1.96 * 0.06/sqrt(36)
Margin of Error : 1.96 * 0.01
Margin of Error = 0.0196
Confidence interval :
xbar ± margin of error
1.22 ± 0.0196
Lower boundary = 1.22 - 0.0196 = 1.2004
Upper boundary = 1.22 + 0.0196 = 1.2396
(1.2004, 1.2396)
C) No, since the confidence interval contains the target filling weight of 1.20.
Since, the internal contains 1.20, then we can conclude that it is filling properly.
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