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Sagot :
Solution :
check_palindrome[tex]$(string)$[/tex]
lower_[tex]$case$[/tex]_string[tex]$=$[/tex] string[tex]$. to$[/tex]_lower()
Let stack = new Stack()
Let queue = new Queue();
for each character c in lower_case_string:
stack.push(c);
queue.enqueue(c);
let isPalindrome = true;
while queue is not empty {
if (queue.remove().equals(stack.pop())) {
continue;
} else {
isPalindrome=false;
break while loop;
}
}
return isPalindrome
Input = aabb
output = true
input =abcd
output = false
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