Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Ask your questions and receive precise answers from experienced professionals across different disciplines. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

When 0.20 mol of hydrogen gas and 0.15 mol of iodine gas are heated at 450 °C until equilibrium is established, the equilibrium mixture is found to contain 0.26 mol of hydrogen iodide. The equation for the reaction is as follows
H2((g) + I2(g) ⇋ 2HI(g)
What is the correct expression for the equilibrium constant, Kc?

Sagot :

Answer:

[tex]Kc=\frac{[HI]^2}{[I_2][H_2]}[/tex]

Explanation:

Hello there!

In this case, for these equilibrium problems it is firstly necessary to know the balanced reaction at equilibrium:

H2((g) + I2(g) ⇋ 2HI(g)

Next, by means of the law of mass action, it turns out possible for us to write the required and correct expression for the equilibrium constant by considering the concentrations and the coefficients in the aforementioned reaction:

[tex]Kc=\frac{[HI]^2}{[I_2][H_2]}[/tex]

Best regards!

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.