Answered

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A wheel with radius 1 foot makes 1 revolution in 4 seconds. What is the linear velocity, in feet per second, of a point on the edge of the wheel? 4π 8π

Sagot :

Answer:

[tex]v=\dfrac{\pi}{2}\ ft/s[/tex]

Step-by-step explanation:

Given that,

A wheel with radius 1 foot makes 1 revolution in 4 seconds

We need to find the linera velocity of a point on the edge of the wheel. We know that, the linear velcity is given by :

[tex]v=r\omega[/tex]

Where

[tex]\omega[/tex] is angular velcocity,[tex]\omega=2\pi\ rad[/tex]

[tex]\omega=\dfrac{1}{4}\times 2\pi\\\\=0.5\pi\ rad/s[/tex]

So

[tex]v=1\times 0.5\pi\\\\v=\dfrac{\pi}{2}\ ft/s[/tex]

So, the linear velocity of the wheel is equal to [tex]\dfrac{\pi}{2}\ ft/s[/tex].

walteragustin

Answer:

pi/2

B

Step-by-step explanation:

Got it right on EG

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