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Sagot :
Answer:
The sum of the first 880 terms in the sequence is 2,273,920.
Step-by-step explanation:
Arithmetic sequence:
The difference between consecutive terms is always the same, called common difference, and the nth term is given by:
[tex]a_{n} = a_0 + (n-1)d[/tex]
In which d is the common difference.
Sum of the first n terms:
The sum of the first n terms of an arithmetic sequence is given by:
[tex]S_{n} = \frac{n(a_1+a_n)}{2}[/tex]
ai = ai-1 + 6
This means that [tex]d = 6[/tex]
In this question:
Sum of the first 800 terms, so [tex]n = 800[/tex]
First term is -53, so [tex]a_1 = -53[/tex]
The 880th term is:
[tex]a_{880} = -53 + (880-1)*6 = 5221[/tex]
Sum
[tex]S_{n} = \frac{880(-53+5221)}{2} = 440(-53+5221) = 2273920[/tex]
The sum of the first 880 terms in the sequence is 2,273,920.
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